Evaluate the following expression using the values given: find x3 − 2y2 − 3x3 + z4 if x = 3, y = 5, and z = −3. −185 −77 −23 85

x^3 − 2y^2 − 3x^3 + z^4

Plug in 3 for x, 5 for y, and -3 for z (given)

(3)^3 -2(5^2) - 3(3^3) + (-3)^4

Simplify

(3)^3 = 3 x 3 x 3 = 27

-2(5^2) = -2 x 25 = -50

-3(3^3) = -3 x 27 = -81

(-3)^4 = -3 x -3 x -3 x -3 = 9 x 9 = 81

Combine all the terms

27 + (-50) - 81 + 81

27 - 50 - 81 + 81

-23 + 0

-23

-23, or (C) is your answer

hope this helps

answer: add the !

step-by-step explanation: then we will answer

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!