Find the volumes of the figures below. i don't need work just answers

Hello!

To find the volume of a square pyramid, use the formula: V = 1/3b²h.

In this formula, b is a side length of the base, and h is height of the figure.

Figure 1

Since we are given the side length of the base, which is 18 inches, and the height, which is 12 inches, we can find the volume.

V = 1/3(18)²(12)

V = 1/3(324)(12)

V = 108(12)

V = 1296 inches³.

The volume of the first figure is 1296 inches cubed.

Figure 2

Since we are not given the height of this figure, we need to find it using the pythagorean theorem. In this case, we need to find a and b. Since the base of this triangle is a square, to find b, it is half the side length of the base.

22 inches / 2 = 11 inches

With the value of b, we can find the height, or a.

a² + 11² = 24²

a² + 121 = 567 (subtract 121 from both sides)

a² = 455 (take the square root of both sides)

a = √455

With the height being √455, we can find the volume.

V = 1/3(22)²(√455)

V = 1/3(484)(√455)

V = (484/3)(√455)

V = 3441.3576..

This can be rounded to 3441.36 inches cubed.

Therefore, the volume of figure two is 3441.36 inches cubed.

what is the answer?