What are the closest two integerrs that √300 is between?

So, we have to see which perfect squares is in between.

Through guess and check, we see that , which evaluate to 289 and 324 respectivly, if under a radicand, would be the two perfect squares closet to the square root of 300.

That means if we were to take the square root of 289 and 324, we should have the two integers that the square root of 300 is in between, and we see that those two numbers are 17 and 18.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

it is x equals 3   plese mark me really need it

step-by-step explanation: