Use the given graph to determine the limit, if it exists. a coordinate graph is shown with a horizontal line crossing the y axis at five that ends at the open point 2, 5, a closed point at 2, 1, and another horizontal line starting at the open point 2, negative 3 and continues to the right. find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x..

for the limit approaching 3 from the right, you want to follow the line to the right of x = 3. from the graph you're describing it sounds like that's y = -3.

the rhs limit is -3 even though f(3) = 7

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)