Mathematics, 13.07.2019 13:30, oglilbrandon
What is the equation of the line that passes through (-3, -1) and has a slope of 2/5 ? put your answer in slope-intercept form. y = 2/5x + 1/5 y = 2/5x - 1/5 y = -2/5x - 1/5
Answers: 1
![\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-1})\qquad \qquad \qquad slope = m\implies \cfrac{2}{5} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=\cfrac{2}{5}[x-(-3)] \\\\\\ y+1=\cfrac{2}{5}(x+3)\implies y+1=\cfrac{2}{5}x+\cfrac{6}{5} \\\\\\ y=\cfrac{2}{5}x+\cfrac{6}{5}-1\implies y=\cfrac{2}{5}x+\cfrac{1}{5}](/tpl/images/0084/9464/b67b5.png)
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What is the equation of the line that passes through (-3, -1) and has a slope of 2/5 ? put your ans...
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