Mathematics, 13.07.2019 14:00, chanthonymjones
Given the function g(x) = 6(4)x, section a is from x = 0 to x = 1 and section b is from x = 2 to x = 3. part a: find the average rate of change of each section. (4 points) part b: how many times greater is the average rate of change of section b than section a? explain why one rate of change is greater than the other. (6 points)
Answers: 1
![\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll}average~rate\\of~change\end{array}\\\\[-0.35em]\rule{31em}{0.25pt}](/tpl/images/0084/9868/035bd.png)
![\bf g(x)=6(4)^x \qquad \begin{cases}x_1=0\\x_2=1\end{cases}\implies \cfrac{g(1)-g(0)}{1-0}\implies \cfrac{6(4)^1-6(4)^0}{1}\\\\\\24-6\implies \boxed{18}\\\\[-0.35em]\rule{31em}{0.25pt}\\\\g(x)=6(4)^x \qquad \begin{cases}x_1=2\\x_2=3\end{cases}\implies \cfrac{g(3)-g(2)}{3-2}\implies \cfrac{6(4)^3-6(4)^2}{1}\\\\\\384-96\implies \boxed{288}](/tpl/images/0084/9868/ca89e.png)
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Given the function g(x) = 6(4)x, section a is from x = 0 to x = 1 and section b is from x = 2 to x =...
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