How many 3 digit numbers can you make using the digits 1 2 3 without being repetitious

Given that such numbers can be repeated the possible combinations are calculated this way: 3*3*3 = 3^3 = 27. This is because you have space for three digits that can be chosen from the set [1,2,3]. So you can make 27 three digit different numbers .

No i refuse to tell you the answer but the estimate is 10