Two points, a and b, are on opposite sides of a building. a surveyor chooses a third point, c, 60 yd from b and 105 yd from a, with angle acb measuring 69.3 . how far apart are a and b (to the nearest yard)?

In the given question it is given that , AC = 105 yd, BC = 60 yd and angle ACB= 69.3 degree.

We have to find the distance of AB, and for that we use law of cosine, which is

Substituting the values of AC, BC and theta, we will get

i dont know sorry

step-by-step explanation:

c. side angle side. u shares the same sides