What is the vertex of f(x)=(x-8)(x-2)

Hello!

To find the vertex of f(x), we can simplify this function into standard form.

f(x) = (x - 8)(x - 2)

f(x) = x² + -10x + 16

With the equation in standard form, we use the formula: x = -b/2a. Then, we substitute the value of x into the equation to solve for the y-value.

x = -(-10) / 2(1)

x = 10 / 2

x = 5

Then, we substitute x = 5 into the original equation.

f(x) = (5 - 8)(5 - 2)

f(x) = -3(3)

f(x) = -9

Therefore, the vertex of f(x) is (5, -9).

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

i’m here for points.