Act ? the graph of a linear function has slope -2/3 and passes through the point (2,1). which of the following points is on the graph of the function? a) (-4,-5) b) (0,4) c) (4,7) d) (8,-3) e) (14,7) you. also, if anyone can link to where i can find more act practice problems/ on this topic i would appreciate it! : )

Hello!

Firstly, we can complete the linear function. To complete it, we need to find the y-intercept of the equation. To find it, we use the equation: y = -2/3x + b, substitute the point (2, 1) into the equation, and solve for b.

1 = -2/3(2) + b

1 = -4/3 + b (add 4/3 to both sides)

b = 7/3

The completed linear equation is: y = -2/3x + 7/3.

The easiest way to find the ordered pair that is on the graph is to graph the equation and label the points (the graph is posted below).

As seen on the graph, the ordered pair, (8, -3), is graphed. To prove it is correct, we can substitute the ordered pair into the linear function.

-3 = -2/3(8) + 7/3

-3 = -16/3 + 7/3

-3 = -3 | True!

Therefore, the answer is choice D, (8, -3).

I don't know any good sites with ACT practice problems, sorry and good luck!

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this