Find the axis of symmetry for this parabola y=-4x^2+8x-12 write your answer as an equation in (y-k)=a(x-h)^2 form

The axis of symmetry is 1.

To find this, do -b/2a, putting -8 in the place of b and -4 in the place of a. Proceed to solve to get 1.

The equation provided is vertex form, so to find the needed components, you need to solve for the vertex. To do so, implement 1 in as x and solve for the vertex.

The vertex is 1, -16.

(y - 16) = -4(x - 1)^2

Although it is not exactly vertex form, the only difference is that instead of it being +k at the end, it is subtracted with the y.

Hope this helps!

think about it deeply and passionately about this property

i am sorry

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116