Write an equation of a line in slope intercept form that is parallel to the line x + 4y = 6 and passes through (-8, 5). show work. write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and passes through the point (2, 6). show work.

Let us find the slope of the line : x+ 4y = 6

we can write it as 4y = -x +6

y = -(1/4) x + ( 6/4)

slope of the line y= mx + b is m

so here slope = m = -1/4

because we have to find a paraller line so the slope for required line would be same : -1/4

equation of the line having slope m and passing through x1 y1 is :

Y= m( X-x1) + y1

let's plug m= -1/4 x1= -8 and y1 = 5

Y= (-1/4) ( X- -8) + 5

Y= ( -1/4) ( x+8) + 5

Y= (-1/4)( X ) + (-1/4)( 8) + 5

Y= (-1/4) x + 3

Let us now work on second part :

given line is : 2x- 3y = 12

let's write it -3y = -2x +12

y= (-2/-3) x + ( 12/ -3)

Y= ( 2/3) x - 4

slope of this line is 2/3

the required line is perpendicular to it

so the slope of required line = negative resiprocal of this slope =

(-1/ slope of this line ) = -1/( 2/3) = -3/2

Equation of line with slope m= -3/2 and passing through x1= 2 and y1 = 6 is :

Y= m( X-x1) + y1

Y= ( -3/2) ( X- 2) + 6

Y= (-3/2) X - 2(-3/2) + 6

Y= ( -3/2 ) X + 9

Answer : for part 1 : Y= ( 2/3) x - 4

Answer for part 2 : Y= ( -3/2 ) X + 9

The slope of the line is .

The equation of the line in slope intercept form parallel to is

Since the above line passes through is

Thus the equation of the line in slope intercept form is

The slope of the line is .

The line perpendicular to the above line has slope

Its equation is . Since this line passes through, ,

.

Thus the equation of the line in slope intercept form is

squares, rhombus, rectangles

5/12, or 5: 12

step-by-step explanation: