2/3[8(5-2)^2 +3*2] how do i distribute the 2/3? and then solve the rest!

To distribute the 2/3, this is what you do.

2/3[8(5-2)^2 + 3*2] = (2/3)(8)(5-2)^2 + (2/3)(3*2) =

Now you can continue. You need to follow the correct order of operations.

= (2/3)(8)(3^2) + (2/3)(6)

= (2/3)(8)(9) + 4

= (2/3)(9)(8) + 4

= (6)(8) + 4

= 48 + 4

= 52

This is how I would have done it.

2/3[8(5-2)^2 + 3*2] =

= 2/3[8(3)^2 + 6]

= 2/3[8 * 9 + 6]

= 2/3[72 + 6]

= 2/3[78]

= 2 * 1/3(78)

= 2 * 26

= 52

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

c

step-by-step explanation:

at least i think its