Arectangle has a width of 50 centimeters and a perimeter of 204 centimeters. what is the rectangle's length?

Let's assume the length of the rectangle be l and width is w.

Given that, the rectangle has a width of 50 centimeters .

So, w = 50.

And Perimeter = 204.

Since, the formula for perimeter of a rectangle is 2l + 2w. So, we can set up an equation as following:

2l +2w = 204

2l + 2(50) = 204 Since, w = 50 is given.

2l + 100 = 204

2l + 100 - 100 = 204 - 100 Subtract 100 from each sides.

2l = 104

Divide each sides by 2 to isolate l.

So, l = 52

Therefore, length of rectangle is 52 centimeters.

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !