Mathematics, 13.07.2019 23:00, janakibubbles7711
When using the inspection method to rewrite the rational expression x^2-10x+14/x-8 , what constant term must the numerator have for to be one of its factors? what number must you add to (and subtract from) the numerator's constant term to derive (x-8) as a factor? for the numerator to have (x-8) as a factor, its constant term must be . to get this number, add and subtract from the numerator’s constant term.
Answers: 1
, we need two numbers m and n to write it as product of two binomials like
, where 
. 
![x^2-10x+c=(x-8)(x+n)\\ \\ Comparing \; x^2+bx+c=(x+m)(x+n) \; with \; above \; equation \;,\\\\ We\; get\; m = -8\; and \; b = -10\\\\ Also \; we \; know, \; m + n = b \; \; and \;\; m \cdot n= c\\ \\ -8+n=-10 \; \ [ Adding \; 8 \; on \; both \; sides]\\ \\ -8+n+8=-10+8 \; [Combining \; like \; terms \; on \; either \; side]\\ \\ n=-2 \\ \\ c=m \cdot n = -8 \cdot -2 = 16](/tpl/images/0086/4555/53754.png)
, we need to add 2 to the constant of the numerator expression to get 
. 
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When using the inspection method to rewrite the rational expression x^2-10x+14/x-8 , what constant t...
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