Solve the following system of equations by substation and select the correct answer below 6x-4y=36 2x-8y=32

6x - 4y = 36

2x - 8y = 32

Solve for y in the first equation. Subtract 6x from both sides.

-4y = 36 - 6x

Divide both sides by -4.

y = -9 + 6/4x

Plug y into the second equation.

2x - 8(-9 + 6/4x) = 32

Distribute -8 inside the parentheses.

2x + 72 - 12x = 32

Combine like terms.

-10x + 72 = 32

Subtract 72 from both sides.

-10x = -40

Divide both sides by -10.

x = 4

Plug x into the first equation.

6(4) - 4y = 36

24 - 4y = 36

Subtract 24 from both sides.

-4y = 12

Divide both sides by -4.

y = -3

x = 4, y = -3

6x - 4y = 36

2x - 8y = 32

I assume you meant "substitution." To solve this system by substitution, first isolate one of the variables in either of the equations. I'll isolate y in the second equation.

2x - 8y = 32 (given)

-8y = 32 - 2x (subtract 2x from both sides)

y = (32 - 2x)/-8 (divide both sides by -8)

y = -4 + 1/4x (simplify)

Substitute -4 + 1/4x for y into the first equation and solve algebraically for x.

6x - 4y = 36 (given)

6x - 4(-4 + 1/4x) = 36 (substitute)

6x + 16 - x = 36 (distribute)

5x + 16 = 36 (collect like terms)

5x = 20 (subtract 16 from both sides)

x = 4 (divide both sides by 5)

Substitute 4 for x into either of the original equations to find y.

6x - 4y = 36 (given)

6(4) - 4y = 36 (substitute)

24 - 4y = 36 (multiply)

-4y = 12 (subtract 24 from both sides)

y = -3 (divide both sides by -4)

Lastly, plug x- and y-values into original equations to check work.

6x - 4y = 36

6(4) - 4(-3) = 36

24 + 12 = 36

36 = 36

2x - 8y = 32

2(4) - 8(-3) = 32

8 + 24 = 32

32 = 32

x = 4 and y = -3; (4, -3).

i think this could be a possible answer (1 / 84) -1

good luck! : d