What is the slope-intercept form of the equation of the line that passes through the points (2, 7) and (4, −1) ? y=−4x+15 y=−4x+12 y=−4x+30 y=−4x+3

Find the slope (m) by using Y2-Y1/X2-X1

Y2 = -1

Y1 = 7

X2 = 4

X1 = 2

(-1 - 7)/((4-2) = -8/2 = -4

Use the point-slope formula to determine the equation. You only need to use one set of points. (2,7) in this case.

(y-Y1) = m(x-X1)

(y - 7) = -4(x - 2)

y-7=-4x + 8

y= -4x + 15

Find the slope (m) by using Y2-Y1/X2-X1

Y2 = -1

Y1 = 7

X2 = 4

X1 = 2

(-1 - 7)/((4-2) = -8/2 = -4

Use the point-slope formula to determine the equation. You only need to use one set of points. (2,7) in this case.

(y-Y1) = m(x-X1)

(y - 7) = -4(x - 2)

y-7=-4x + 8

y= -4x + 15

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)