Math problem and i don't know how to do 14 brian and richard stand back-to-back. each boy takes 5 equally spaced steps, in opposite directions from the starting location. at this point, richard walks to where brian is now and does so in 9 steps. how many times bigger are richard's steps than brian's steps?

Let Brian's steps have a measure of 1, and Richard's steps have a measure of k. Then after each walks 5 steps away from the other, their distance apart is

... 5 + 5k

We are told that distance is equal to 9 of Richard's steps, so is equal to 9k.

... 5 + 5k = 9k

... 5 = 4k . . . . . . . subtract 5k

... 5/4 = k . . . . . . divide by 4

Richard's steps are 5/4 the size of Brian's steps. The appropriate selection is

... b) 5/4

6 cars because if you have 8 and subtract 2 youll have 6 left over