Asap pluse properties of limits to find the indicated limit. it may be necessary to rewrite an expression before limit properties can be appliedlimx→1  x3+5x2+3x−9x−1a. 16b.-16c.0

I'm guessing what's really being asked is

Since x=1 is a root of the numerator, we can factor out x-1 which then will cancel with the denominator. Here's the long division; sorry about the lame formatting.

__ x^2 + 6x + 9

x-1 | x^3 + 5x^2 + 3x -9

___ x^3 - x^2

_______ 6x^2 + 3x

_______ 6x^2 - 6x

____________ 9x - 9

____________ 9x - 9

16

Choice a

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8