It took mark 6 hours to drive from his college to his home. the next week he drove the same distance from his home back to his college in 5 hours. if the average rate for his first trip was r miles per hour, what was the average rate for the second trip, in terms of r ?

We need to use the following formula of distance .

Distance= speed * time .

For the first time

distance = 6r

And let the average rate for the second time be s

So distance = 5s

Since distance remains same, so we get

6r=5s

Now we have to solve for s. And for that we need to get rid of 5, by dividing both sides by 5, that is

And that's the required average rate for the second trip .

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

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step-by-step explanation: