1.what is the y-intercept of the plane whose equation is 4x + 5y – z = 20? (5, 0, 0) (0, 5, 0) (0, 4, 0) (0, 0, 4) 2.which equation has intercepts at x(1, 0, 0), y(0, –1, 0), and z(0, 0, 2)? 3x – 2y + 6z = 12 4x – 4y + z = 4 x – y + 2z = 4 2x – 2y + z = 2 5.is attached below

Option c and

Option d

Step-by-step explanation:

Given is a plane

To find y intercept

In the y axis x=0=z

Substitute to get

Hence point is (0,4,0)

2) When x intercept = 1, y int =-1 and z int =2 we have in intercept form the plane

is the right one

Option d

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: