The angle a is acute and sec a=k. find in terms of k the value of cosec a. can u guys put in the process ?

Fundamentally you can get there using the identity

... sin(a)² + cos(a)² = 1

... 1/cosec(a)² + 1/k² = 1 . . . . . substituting for sec(a) and sin(a)

... 1/cosec(a)² = 1 - 1/k² = (k² -1)/k² . . . . subtract 1/k²

... cosec(a)² = k²/(k² -1) . . . . . Multiply by cosec(a)²k²/(k²-1)

... cosec(a) = k/√(k²-1) . . . . . .take the square root

You can get there slightly faster using the identities tan²=sec²-1; csc=sec/tan.

77

step-by-step explanation:

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.