An integer is one more than four times another. if the product of the two integers is 39, then find the integers

Let’s say the integers are x and y. x = 1 + 4y, as the problem says. The problem also says that x * y = 39.

We can substitute 1 + 4y for x and get:

(1 + 4y) * y = 39

Distribute:

y + 4y^2 = 39

Subtract 39 from both sides:

4y^2 + y - 39 = 0

Factor:

(4y + 13) * (y - 3) = 0

Solve for y:

y can equal -13/4 or 3

The problem says that y must be an integer, so we cross off -13/4, giving us y = 3.

Use y to solve for x:

x = 1 + 4 * (3) = 13

So, y = 3 and x = 13.

3x3 = 9 and 2x2 = 4

step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions