50 points fran has a bag with 20 marbles in it. some of the marbles are blue, some are green, and some are yellow. she draws one marble at random, records the color, and returns it to the bag. here is her data after 1200 trials: blue 845 green 305 yellow 50 estimate the probability that a marble drawn at random will be blue. estimate the probability that a marble drawn at random will be green. estimate the probability that a marble drawn at random will be yellow. express each probability estimate as a fraction with 20 in the denominator.

Our initial estimate we have for the probabilities is

Blue 845/1200

Green 305/1200

Yellow 50 /1200

We multiply by 20 to get the numerator when the denominator is twenty. This is an estimate of the number of marbles of each color;

Since we know there are a whole number of marbles, our best estimate of the probabilities is

Blue 14/20 Green 5/20 Yellow 1/20

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%