As part of proof find the midpoint of pq

P(0,0) and Q(2a , 0)

Midpoint PQ

x = (x1 + x2)/2 and y = (y1 = y2)/2

Midpoint:

x = (2a +0)/2

= 2a / 2

= a

y = (0+ 0)/2

= 0/ 2

= 0

So midpoint PQ (a , 0)

Answer is the 1st option

(a, 0)

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

me! what did you put for this question?

step-by-step explanation: