Subtract the equations 3x plus 4y equals 17 minus ( 3x plus 2y equals three )

The problem we are asked to simplify is:

(3x + 4y = 17) - (3x + 2y = 3)

To subtract the equations, we do what we would normally do, combine like terms. This gives us our answer equation of:

(3x - 3x) + (4y - 2y) = (17 - 3)

This gives us our answer of:

2y = 14

But, if we would want to solve it (the question doesn't ask us for this), we find that y = 7 and substitute the value of y in one of the equations to find x.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

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