Identify an equation in slope intercept form for the line parallel to y equals 4x -9 that passes through (-5,3)

Slope intercept form of a line is y=mx+b where m= slope and b=y-intercept.

Now compare this form with the tiven equation y=4x-9 to get the value of m.

So, m= 4.

Slope of all parallel lines are always equal. Which means the line which is parallel to this has also the same slope: m=4.

Now we need to find the value of b to get the equation. That parallel line passes through (-5,3).

The point intercept form of a line is,

(y-y1)=m(x-x1)

So, we can plug in the m=4, x1=-5 and y1=3 in the above equation. Hence,

y-3=4(x-(-5))

y-3=4(x+5) Since -(-5)=+5

y-3=4x+20 By distributing property.

y=4x+20+3 Adding 3 to each sides.

y=4x+23

So, the slope-intercept form of that parallel line is y=4x+23.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

y=1/4x-4

step-by-step explanation: