The coordinates of quadrilateral fghj are f(-5, -3), g(-3, 3), h(3, 5), and j(7, -1). find the midpoint of line fg. (-4, 0) (5, 2) (1, -2) (0, 4)

To find the midpoint of line FG, we have to use the following midpoint formula , which is

In the given question,

x1= -5, y1= -3 , x2=-3, y2=3

Substituting the values of x1,y1,x2 and y2 in the formula of the midpoint, we will get

So the midpoint of the given line is (-4,0) and hence the correct option is the first option .

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

step-by-step explanation: