If dr. i. m. smart mixes 50ml of a 20% acid in water solution with 30ml of acid, what is the quantity and concentration of the final solution?

80ml of the solution with a 50% acid concentration.

Step-by-step explanation:

Amount of acid in the water solution:

50ml * 20%= 10 ml

∴There is 10ml of acid in the solution.

Final amount of liquid:

50ml + 30ml = 80ml

Final amount of Acid:

10ml + 30ml = 40 ml

Concentration of Acid in Solution

40ml / 80ml = 0.5 = 50%

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

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step-by-step explanation: