Assuming boys and girls are equally likely, find the probability of a couple having a baby boy when their sixth child is born, given that the first five children were all boys.

It is given that boys and girls are equally likely so the probability of getting boy or girl on any birth is 1/2= 0.5

Now we know that getting boy or girl is independent of each other.

So getting boy or girl on previous birth does not affect the probability of getting boy or girl on next birth. So probability of getting boy or girl on each birth is same 0.5

The probability of getting baby boy on sixth birth given first five are girl is same as getting baby on sixth birth.

P(Getting boy on sixth birth ) = 1/2 = 0.5

So the probability of getting baby boy on sixth birth given first five are girl is 0.5

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

from the sentence, "tomorrow morning, akiko will arrive an hour late" depicts a third person perspective because it doesn't use any pronoun to replace akiko, the subject of the sentence, and it is in singular form since akiko is only one person.