Simplify the expression by combining like terms. 16+8a−3a+6b−9 5a+6b+7 11ab+7 5a+6b−9 16+11ab−9

Answer is 5a + 6b + 7

16 + 8a - 3a +6b -9 subtract 3a from 8a which is 5a

16 + 5a + 6b -9 Now subtract 9 from 16

7 +5a +6b Now reorder them by the first letter in the alphabet and then regular numbers last.

5a + 6b + 7

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5