Mathematics, 14.07.2019 09:00, narwalmaster2001
Algebra 2 . solving equations containing two radicals
Answers: 1
![\sqrt[3]{5x-2} -\sqrt[3]{4x} =0\\ \\ \sqrt[3]{5x-2} =\sqrt[3]{4x}\\ \\ (\sqrt[3]{5x-2} )^3=(\sqrt[3]{4x})^3\\ \\ 5x-2=4x\\ \\ 5x-4x=2\\ \\ x=2](/tpl/images/0088/0420/a0882.png)
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