Mathematics, 14.07.2019 09:30, kenzyxyz2127
Sin^2theta=8(cos(-theta)-1). solve the equation on the interval 0
Answers: 1
we can simplify inside the parenthesis first. Since cos(-theta) = cos(theta), we can rewrite as 
. We can distribute the 8 into the parenthesis to get 
. The idea is to solve for the angle theta. So we have to use the fact that sin^2 theta is the same as cos^2theta - 1. Trig identity. 
.
. We will factor this to solve for theta. It will be easier if we make a u substitution. Let u = cos theta; therefore, u^2 = cos^2 theta. Like this: 
. That factors very easily to u = 7 and u = 1. Replacing the u with cos theta: 
and 
. Since cosine only exists between 1 and -1, there is no solution for 
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Sin^2theta=8(cos(-theta)-1). solve the equation on the interval 0...
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