Answer asap. will mark ! a) the mass of an empty bucket b) the mass of the bucket containing 1 liter of liquid c) the mass of one liter of liquid d) the volume of the liquid in the bucket, if the total mass of bucket with the liquid is 3 kg

I started this and got distracted and never finished and it timed out. Focus Dean.

It's not the best graph; I assume the origin is the apparent origin and the y axis numbers go with the line above them.

This graph is M(V), M(V) is mass in kg of bucket with water volume V in liters

a) the mass of an empty bucket

That's the y intercept, M(0), eyeballing it around .7 kg

.7 kg

b) the mass of the bucket containing 1 liter of liquid

That's M(1), looks like 1.3 or so

1.3 kg

c) the mass of one liter of liquid

That's the difference, M(1)-M(0), about .6 kg. We can get a better estimate from a longer slope, say (.5,1) to (3,3), (3-1)/(3-.5) = .8 kg.

Answer : 0.8 kg

d) the volume of the liquid in the bucket, if the total mass of bucket with the liquid is 3 kg.

Solve M(V)=3

That has a solution from the graph V=3.

3 liters

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19

i can you with this question sweetie!

step-by-step explanation: