Astudent solved the following problem and made an error: triangles abc and def. angles a and f are congruent and measure 135 degrees. coordinates for the vertices are at a 0, 2 and b 2, 4 and c 0, 0 and d 2, 0 and e 4, 4 and f 4, 2. line 1 segment ac equals 2. segment fe equals 2. segment ac is congruent to segment fe line 2 ∠a ≅ ∠f line 3 length of segment ab. a (0, 2) b (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment ab = 2.83 line 4 length of segment de. d (2, 0) e (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment de = 4.47 line 5 segment ab is congruent with segment de line 6 triangle abc is congruent with triangle fdeby sas in which line did the student make the first mistake? line 2 line 5 line 3 line 4