Jacob is solving the equation 3√3q = 27 for q. his work is shown. 3√3q = 27 √3q = 9 (√3q)^ = 9^ 3q = a q = b what are the correct values for a and b? (^ stands for squared)

The given problem is stated as below:

3√3q = 27

√3q = 9

(√3q)^ = 9^

(^ stands for squared )

3q = A

Therefore we have,

A = 9^

or, A = 81

Again it is given that,

3q = A

or, 3q = 81.

or, q = 81/3 = 27

q = 27

As per the problem q = B,

therefore we can conclude that B = 27

So by solving the problem we get the final answer as below:

A = 81 and B =27

step-by-step :

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional