Mathematics, 14.07.2019 11:00, kaquino983
Acircle is centered at the point (5, -4) and passes through the point (-3, 2). the equation of this circle is (x + __ )^2 + (y + __ )^2 = __ .
Answers: 1
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{5}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[-3-5]^2+[2-(-4)]^2}\implies r=\sqrt{(-3-5)^2+(2+4)^2} \\\\\\ r=\sqrt{(-8)^2+6^2}\implies r=\sqrt{100}\implies r=10\\\\ -------------------------------](/tpl/images/0088/3805/4f9d4.png)
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{5}{ h},\stackrel{-4}{ k})\qquad \qquad radius=\stackrel{10}{ r} \\\\\\\ [x-5]^2+[y-(-4)]^2=10^2\implies (x-5)^2+(y+4)^2=100](/tpl/images/0088/3805/540f9.png)
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Acircle is centered at the point (5, -4) and passes through the point (-3, 2). the equation of this...
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