Can you me ? i think i figured it out but am not sure . you !

Thank you for posting the figure. Without it, I would have thought the parabola has a vertical axis.

For a parabola with a horizontal axis (as in this case), the equation of the parabola is

f(y)=a(y-k)^2+h

where (h,k) is the vertex.

Substituting (h,k)=(2,-4),

f(y)=a(y+4)^2+2(1)

as the equation of the parabola, with the value of "a" yet unknown.

Since we are given that the parabola passes through the point (-3,-3), we can substitute the corresponding x,y values in (1) to solve for a.

f(y)=-3=a(-3+4)^2+2

solve for a

a=(-3-2)/(1^2)=-5

So the equation of the parabola is f(y)=-5(y+4)^2+2

.25

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it