Solving quadratic equationsfirst drop menu has the options a, b, c, d. the second drop menu has the options minimum and maximum. the third drop menu has the options -1, 0, 2, and 5. and the last drop menu has the options -1, 5, 12, and 15.

The first answer is Equation B. y = -3(x - 2)^2 + 5. This is because this is the only equation that is in vertex form.

The second answer is maximum. This is because the leading coefficient of this equation is negative, therefore the parabola opens down and has a maximum.

The third (and fourth) answer is (2,5). Using the vertex form, y = a(x - h)^2+k, the vertex is (h,k). In this instance, the vertex is (2,5).

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step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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