40 points match the one-to-one functions with the graphs of their inverse functions.

for the first function:

1)

f(x)=20-x

The inverse function is given as:

f(x)=y

20-x=y

i.e.

x=20-y

Hence, the inverse function satisfies the equation:

f(x)=20-x

2)

Now,

f(x)=y

Hence, the equation of inverse function is:

Hence, the graph of inverse function has asymptotes at x=1 and also passes through (0,0).

3)

f(x)=20x

f(x)=y

20x=y

so, the inverse function is:

Hence, the graph of this function is a straight line passing through (0,0)

4)

Let f(x)=y

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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