Find the 6th term of the geometric sequence, given the first term and common ratio a1= 5 and r=3/2

Answer

37.96875

Explanation

In geometric sequence we use the formula below to find the nth of a sequence.

Tn = ar⁽ⁿ⁻¹⁾

Where a ⇒ first term

n ⇒ the term we are looking for

T₆ = 5 × (3/2)⁶⁻¹

= 5 × (3/2)⁵

= 5 × 243/32

= 1215/32

= 37 31/32

= 37.96875

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )