Suppose 200 tickets were sold for a particular concert. some tickets cost $10 each, and others cost $5 each. if total ticket sales were $1,750, how many of the more expensive tickets were sold.

Let the 5 dollar tickets sold be x and the 10 dollar tickets be y. We can then create a system of equations to solve for the amounts.

This equation is the total amount of tickets sold.

x+y=200

This equation deals with the total amount of money made.

5x+10y=1750

Lets multiply the first equation by 5 on both sides.

5(x+y)=5(200)

5x+5y=1000

Now we use the elimination method by subtracting one equation from the other.

5x+10y=1750

-(5x+5y=1000)

0+5y=750

Next, we can solve for y in this equation.

5y=750

y=150

So, 150 of the more expensive ticket was sold. Finally, we can plug in y into one of the equations and solve for x.

x+150=200

x=50

Thus, 50 of the less expensive tickets were sold.

yeet

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~