Suppose that in a random selection of 100 colored candies, 24% of them are blue. the candy company claims that the percentage of blue candies is equal to 28%. use a 0.10 significance level to test that claim.

Null hypothesis: p= 0.28

Alternative hypothesis: p not equal to 0.28

Critical value at is 1.645

Since, z=-0.89 lies between -1.645 and 1.645 we fail to reject the null hypothesis.

The lies between and we fail to reject the null hypothesis.

Step-by-step explanation:

Given: Suppose that in a random selection of colored candies, of them are blue. the candy company claims that the percentage of blue candies is equal to .

According to question:

Null hypothesis:

Alternative hypothesis: not equal to

Now, is caluculated as:

Critical value at   is

Therefore, lies between and we fail to reject the null hypothesis.

Learn more about Null hypothesis here:

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6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.