Isosceles right triangle abc has a hypotenuse, ab, with a length of 18 feet. find the exact lengths of the other two sides, ac and bc. ac = a0√ a1 feet bc = a2√ a3 feet to the nearest square foot, find the area of abc . area of abc = a4 square feet

we know that

if ABC is an isosceles right triangle

then

side AC=side BC

angle A=angle B=45 degrees

cos B=adjacent side angle B/hypotenuse

adjacent side angle B=BC

hypotenuse=AB> 18 ft

angle B=45 degrees

cos 45°=(√2)/2

so

cos 45°=BC/AB> solve for BC

BC=AB*cos 45> BC=18*(√2)/2> BC=9√2 ft

AC=BC> AC=9√2 ft

the answer part 1) is

the exact lengths of the two sides, AC and BC is

AC=9√2 ft

BC=9√2 ft

Part b) Find the Area of triangle ABC

Area=b*h/2> AC*BC/2> (9√2)*(9√2)/2> 81 ft²

the answer part b) is

the area of triangle ABC is equal to 81 ft²