Mathematics
Mathematics, 14.07.2019 19:00, hwhite41

What equations can i use to find the lengths of the legs of a 24 square foot triangle

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Mathematics, 23.07.2019 14:30, Wintersavannah
The area of the right triangle shown is 24 square feet. which equations can be used to find the lengths of the legs of the triangle? check all that apply. a x2 + 2x – 24 = 0 b x(x + 2) = 24 c x2 + (x + 2)2 = 100 d 0.5(x)(x + 2) = 24 e x2 + 2x – 48 = 0 f x2 + (x + 2)2 = 24
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Mathematics, 08.10.2019 23:30, kat5377
The area of the right triangle shown is 24 square feet. which equations can be used to find the lengths of the legs of the triangle? check all that apply. 0.5(x)(x + 2) = 24 x(x + 2) = 24 x2 + 2x – 24 = 0 x2 + 2x – 48 = 0 x2 + (x + 2)2 = 24 x2 + (x + 2)2 = 100 me quickly, i really need the . i'll even mark brainiest if you do it correctly. i really need this and i need whoever does this to pay attention to the whole "check all that apply". i'm adding the picture below.
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Mathematics, 17.10.2019 01:00, Jasten
The pythagorean theorem deals with which relationship in a right triangle? the sum of the two angles and the right angle the lengths of the legs and the length of the hypotenuse. the ratio of the two legs. the perimeter of the triangle and the hypotenuse. the lengths of the sides of a triangle are 3, 3, . can the triangle be a right triangle? yes or no? the lengths of the sides of a triangle are 4, 5, 6. can the triangle be a right triangle? yes or no? the lengths of the sides of a triangle are 6, 8, 10. can the triangle be a right triangle? yes or no? a = 5, b = 12, c = √(34) √(119) √(154) 13 a = 8, b = 15, c = 17 √(24) √(46) √(161) a = 16, c = 20, b = 2√(2) 12 4√(23) 4√(41) a = 40, c = 41, b = 1 9 57 81 the lengths of the sides of a triangle are 3, 4, 5. can the triangle be a right triangle? yes or no?
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Mathematics, 09.11.2019 08:31, mxlx27
The area of the right triangle shown is 24 square feet.which equations can be used to find the lengths of the legs of the triangle? check all that apply. 0.5(x)(x + 2) = 24 x(x + 2) = 24 x2 + 2x – 24 = 0 x2 + 2x – 48 = 0 x2 + (x + 2)2 = 24 x2 + (x + 2)2 = 100
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