Look at the graph shown: a coordinate plane graph is shown. a line passes through the y-axis at 3 and through the point 2 comma 4. which equation best represents the line? y = 3x + 3 y = 1 over 2 x − 3 y = 1 over 2 x + 3 y = 3x + 1 over 2

Using the information given, one can solve to find the equation of the line using slope intercept formula y=mx+b.

Given the y-intercept, b, 3.

y=mx+3

Next, we can plug in the given point (2,4), to solve for the slope.

4=m(2)+3

Subtract 3 from both sides.

1=2m

divide by 2.

1/2=m

So, given m and b, you can make your equation:

y=1/2x+3

I believe that is answer choice C. Hope this helps!

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!