Maria has five books in her book bag. three books are novels, one is a biography, and one is a poetry book. today she grabs one book out of her bag without looking and returns it later. tomorrow she does the same thing. which is the probability that she grabs a novel both days?

The probability would be "3/5."

There is three novels in her book-bag.

There are 5 books in all.

So the chances you might get a novel would be 3.

Therefore the probability would be 3/5!

Probability is the amount of what would happen. So in this case if there are three novels there would be three possible outcomes. But there are 5 books in all so the chances are that you will get a novel would be 3 out of 5. Which would mean the probability is 3/5!

Hope this helps!

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3