Given a rectangle with a side of 10m and a dialogue of 26m. find the perimeter of the rectangle.

To find the longer side, use the Pythagoream theroem. 26m is the hypotenuse.

Pythagoream theorem: a² + b² = c² or c² - a² = b², in which "c" is the hypotenuse, and a and b can be used interchangeably.

c = 26

a = 10

b = b

Plug into corresponding areas.

c² - a² = b²

(26)² - (10)² = b²

Simplify.

26 x 26 = 676

10 x 10 = 100

676 - 100 = b²

b² = 576

Isolate the b. Root both sides

√b² = √576

b = √576

Simplify the root

b = √576

b = 24

The longer side of the rectangle = 24 m

To find the perimeter, use the 2l + 2w = P formula.

w = width = 10

l = length = 24

P = perimeter

2(24) + 2(10) = P

Simplify

48 + 20 = P

Add

68 = P

68 meters is your perimeter

hope this helps