Stacey is selling tickets to the school play. the tickets are $6 for adults and $4 for children. she sells twice as many adult tickets as children's tickets and brings in a total of $352. how many of each kind of ticket did she sell?

Stacey sold 22 children's tickets and 44 adult tickets.

Step-by-step explanation:

Let a and c represent the numbers of tickets sold.

Then a = 2c   (twice as many adult tickets as children's tickets)

Then the equation relating the dollar amounts is

($6/ticket)(2 c) + ($4/ticket)(c) = $352

Then $12c + $4c = $352, so $16c = $352.

Solving this for c, we get 22.  Then a = 2c = 2(22) = 44

Stacey sold 22 children's tickets and 44 adult tickets.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

5/12, or 5: 12

step-by-step explanation: