An airplane is traveling at a speed of 200 miles/hour with a bearing of 240°. the wind velocity is 60 miles/hour at a bearing of 25°. what are the plane's actual speed and direction angle?

This is a vector problem so we will split it by components and add them.

x direction

200sin(240) + 60sin(25) = -147.847985

y direction

200cos(240) + 60cos(25) = -45.6215327

To find the actual speed we now find the magnitude

(-147.847985)^2 + (-45.6215327)^2 = c^2

c = 154.72669748 mph

To find the direction we can do arctan of the different directions:

arctan(-147.847985/-45.6215327) = 252.85 degrees.

So the plane is going 154.73 mph at 252.85 degrees :)

<154.72, 197.15 degrees> (D)

Step-by-step explanation: I got this right on Edmentum

kk.bj.

step-by-step explanation:

.mnm.kn.kj

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!